SOLUTION: Let p1 be the proportion of successes in the first population and let p2 be the proportion of successes in the second population. Suppose that you are testing the hypotheses: Ho

Question 457487: Let p1 be the proportion of successes in the first population and let p2 be the proportion of successes in the second population. Suppose that you are testing the hypotheses:
Ho:p1-p2=0
Ha:p1-p2 does not equal 0
Futhermore suppose that Z*=1.73, find and input the p-value for this test. Round your answer to 4 decimal places.
This is what I did, but I'm not sure if it is right.
This is how I drew my curve ("////" means that area is shaded)..
/////(-1.73)_______0_______(1.73)//////
So.. on TI-83, I did: normalcdf (-9, -1.73) = 0.0418
then I multiplied it by 2 because there are 2 shaded regions:
-1.73 --> -infinity
and
1.73 --> infinity
So the p-value that I got was: 0.0836
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'm assuming that Z* is the test statistic (it could easily be the critical value). Without more information, I cannot verify if that is the correct value for the test statistic (since I would need to know x1, x2, n1, and n2)

Ignoring these little details, if Z* = 1.73 is the test statistic, then you are correct in saying that the p-value is 0.0836

Now if your significance level alpha is 0.01 or 0.05, then you would fail to reject the null hypothesis (since the p value is larger than alpha).

On the other hand, if the significance level alpha is something like 0.1, then you would reject the null hypothesis (since the p-value is smaller than alpha).

If the significance level is not stated or given, then assume it to be 0.05 (usually the default significance level in many cases)

Overall, it seems like a lot of info is missing. Please post more info if you can.
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