SOLUTION: Could you please help me to solve this part question.
Must show work.
A population has a normal distribution with a mean of 130 and a standard deviation of 30. Find the pro
Algebra.Com
Question 456928: Could you please help me to solve this part question.
Must show work.
A population has a normal distribution with a mean of 130 and a standard deviation of 30. Find the probability that a single element selected from the population will have a value between 139.50 and 167.25.
Use the population described in problem 2 above. Now find the probability that the sample mean for a sample of 16 elements selected from the population will be between 139.50 and 167.25.
Explain the reason the answers to the above are different.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A population has a normal distribution with a mean of 130 and a standard deviation of 30. Find the probability that a single element selected from the population will have a value between 139.50 and 167.25.
---
z(139.5)=(139.5-130)/30 = 0.3167
z(167.25)=(167.25-130)/30 = 1.2417
---
P(139.5< x < 167.25) = P(0.3167< z <1.2417) = 0.2686
============================================================
Use the population described in problem 2 above. Now find the probability that the sample mean for a sample of 16 elements selected from the population will be between 139.50 and 167.25.
-------
t(139.5)=(139.5-130)/[30/sqrt(16)] = 1.2667
t(167.25)=(167.25-130)/[30/sqrt(16)] = 4.9667
=============
P(139.5 < x-bar < 167.25) = P(1.2667 < t < 4.9667 when df = 15) = 0.1122
=========================================================
Cheers,
Stan H.
=============
RELATED QUESTIONS
Could you please help me to solve this problem?
Must show work
A sample of 20... (answered by edjones)
Please help me to solve this problem...
A normal distribution has a mean of 36 and a... (answered by stanbon)
Could you please help me to solve this question
Must show work
A sample of 100... (answered by stanbon)
Could you please help me to solve this problem?
A binomial probability distribution... (answered by stanbon)
Assuming the population has a normal distribution. A sample of 25 randomly selected... (answered by stanbon)
Let x = red blood cell (RBC) count in millions per cubic millimeter of whole blood.... (answered by stanbon)
Good morning everyone, I have a hard time finding a answer for this question. I assumed... (answered by rothauserc)
Could you please help me to solve this problem?
Must show work
Football is the most... (answered by stanbon)
I'm desperate. This is the last question I have left. I have done the rest, PLEASE... (answered by stanbon)