Question 451934: In 1992, the FAA conducted 86,991 pre-employment drug tests on job applicants who were to be engaged in safety and security-related jobs, and found that 1,143 were positive. (a) Construct a 95 percent confidence interval for the population proportion of positive drug tests
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In 1992, the FAA conducted 86,991 pre-employment drug tests on job applicants who were to be engaged in safety and security-related jobs, and found that 1,143 were positive.
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p-hat = 1143/86991 = 0.013
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(a) Construct a 95 percent confidence interval for the population proportion of positive drug tests
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SE = 1.96*sqrt[0.013*0.987/86991] = 0.000753
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95% CI: 0.013-0.000753 < p < 0.013+0.000753
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Cheers,
Stan H.
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