Hi,

10 chips in all (4-w,5-p,1-b)

Chips are selected randomly one at a time, and are "not replaced".

Find the probability of the following. 

a) purple chip then black = 5/10*1/9 

b) black chip then white chip = 1/10*4/9

c) 2 purple chips = 5*10*4/9

d) white chip, then purple chip, then black chip = 4/10*5*9*1/8

e) 3 white chips = 4/10*3/9*2/8

f) black chip, then white chip, then red chip = 0  (no red chips) 

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!
 





a)  There are 5 purple chips out of 10 total chips, so the probability of picking a purple chip on the first draw is 1/2.  Then, given a purple was picked on the first draw with no replacement, there is 1 black chip out of 9 remaining chips, so 1/9.  1/2 times 1/9 = 1/18.





Sorry, you only get one problem answered per post.





John



My calculator said it, I believe it, that settles it



 

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