SOLUTION: The scores on a certain test are normally distributed with a mean score of 43 and a standard deviation of 3. What is the probability that a sample of 90 students will have a mean

Question 449735: The scores on a certain test are normally distributed with a mean score of 43 and a
standard deviation of 3. What is the probability that a sample of 90 students will have a
mean score of at least 43.3162?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The scores on a certain test are normally distributed with a mean score of 43 and a standard deviation of 3. What is the probability that a sample of 90 students will have a mean score of at least 43.3162?
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t(43.3162) = (43.3162-43)/[3/sqrt(90)]
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= (0.3162)/[0.3162] = 1
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P(x-bar >= 43.3162) = P(t > 1 when df = 89) = 0.1600
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Cheers,
Stan H.
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