Hi,

The scores on a standardized college entrance examination are found to be normally distributed.

The mean is 85 and the standard deviation is 11

What percent scored between 85(Note: the mean) and 107?

 z = (107-85)/11 = 22/11 = 

 P(x < 207) = P(z< 2) =  NORMSDIST(2) = .9773

  .9773 - .5 = .4773   47.73% are between 85 and 107

Area under the graph from the y-axis to the blue line

 

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