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P(Both Male) = P(Male AND Male)
P(Both Male) = P(Male)*P(Male)
P(Both Male) = (4/11)*(3/10)
P(Both Male) = 12/110
P(Both Male) = 6/55
Notes: there are 4+7 = 11 kittens total. Because the kittens are NOT being replaced, this means that this total will go down with each kitten being given away. So on the first giveaway, there are 4 males (out of 11 total) and on the second giveaway there are 3 (4-1 = 3) males out of 10 (11-1 = 10).