SOLUTION: suppose a fair coin is tossed twice. Find the probability of getting exactly one head is?
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Question 448034: suppose a fair coin is tossed twice. Find the probability of getting exactly one head is?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
There are two ways to figure this. Since there are only four possible outcomes for tossing two coins, you can simply enumerate them and count the successes.
Failure: 2 heads
Success: 1 head
Success: 1 head
Failure: 0 heads
Two successes out of four possiblities. Probablity is 1/2.
Or you can get fancy and use the formula for the probability of 
successes in 
trials where 
is the probability of success on any given trial:
\ =\ \left(n\cr k\right\)\left(p\right)^k\left(1\,-\,p\right)^{n\,-\,k})
Where )
is the number of combinations of things taken at a time and is calculated by !})
Or for your problem:
\ =\ \left(2\cr 1\right\)\left(0.5\right)^1\left(0.5\right)^1\ =\ 2\,\cdot\,0.5\,\cdot\,0.5\ =\ 0.5)
John
My calculator said it, I believe it, that settles it
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