SOLUTION: If the probability of any individual being in an airplane accident is .0005 in any given year, what is the probability of that same individual being in three separate, unrelated a

Question 44721: If the probability of any individual being in an airplane accident is .0005 in any given year, what is the probability of that same individual being in three separate, unrelated airplane accidents in a single year? Explain your answer. Please help me figure this one out. Thank you so much.
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Since the events are unrelated and independent of each other, their probabilities multiply...this is what is called the logical "AND" case...as in, what is the probability that this AND that will happen...in this particular problem there are three things...so the probability is
P(3 accidents) = .0005^3 = .000000000125 = 1.25 x 10^-10
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