SOLUTION: How many four letter code words can be formed using a standard 26 letter alphabet if repetition is allowed? and then if repetition is not allowed?

Question 44688: How many four letter code words can be formed using a standard 26 letter alphabet if repetition is allowed? and then if repetition is not allowed?
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Any of 26 letter can be in any of 4 spots, so there are 26^4 = 456,976 possibilities
If there is no repeating, then the answer is less, because, even though 26 letters can be first, only 25 can be second, 24 can be third, and 23 can be last, so we get
26 x 25 x 24 x 23 = 358,800 possibilities
RELATED QUESTIONS
How many seven-letter code words can be formed using a standard 26 alphabet if repetition (answered by ikleyn)

How many five letter words can be made from the alphabet if repetition is... (answered by stanbon)

How many five-letter codes can be formed, using the alphabet, if repetition of letters is (answered by tommyt3rd)

How many 5 letter code words can be formed using a 27 letter alphabet? A-repetitions... (answered by Theo)

How many different four-letter words can be formed from the letters: a,b,c,d,e,f, and g... (answered by edjones)

How many seven letter code words can be formed using a standard 26 letter alphabet if... (answered by VFBundy,Edwin McCravy)

How many three-letter code symbols can be formed using a set of 5 different letters if... (answered by checkley77)

From the letters of the word HONESTY,how many ways 3- letter words can be formed,if... (answered by Edwin McCravy)

How many four-letter "words" can be made from 6 letters "AEBWDP" if repetition of... (answered by ikleyn)