Hi
IQ scores that are normally distributed with aof 105 and a of 20
Find
*Note:
lower 14% then z = -1.0803 NORMSINV(0.14)
-1.0803 = (x - 105)/20
105 - 20*1.0803 = 83.394
top 86% then z = 1.0803 NORMSINV(0.86)
105 + .20*1.0803 = 126.606
126.6 - 83.4 = 43 IQ points separating the bottom 14% from the top 86%.