In one region, the September energy consumption levels for single family homes are found to be normally distributed with a mean of 2995 kwh and a standard deviation of 1050 kwh. a. for a randomly selected home, find the probability that the September energy consumption level is below 200 kwh. Note: If you are supposed to use z-scores and tables instead of the TI-83 or better calculator, then post again, as I'm only going to tell you how to do it with the calculator. On your TI-83 or better calculator: Press 2nd VARS [to get DIST menu] Press 2 [to get normalcdf( ] After " normalcdf( " type this: -10^99, 200, 2995, 1050) so that you see this on the main screen normalcdf(-10^99,200,2995,1050) Then press ENTER and you read .0038850368 ===================================== b. for a randomly selected home, find the probability that the September energy consumption level is between 2100 kwh and 2200 kwh On your TI-83 or better calculator: Press 2nd VARS [to get DIST menu] Press 2 [to get normalcdf( ] After " normalcdf( " type this: 2100,2200,2995,1050) so that you see this on the main screen normalcdf(2100,2200,2995,1050) Then press ENTER and you read .0274807743 ========================================== c. for a randomly selected home, find the probability that the September energy consumption level is above 1900 kwh. On your TI-83 or better calculator: Press 2nd VARS [to get DIST menu] Press 2 [to get normalcdf( ] After " normalcdf( " type this: 1900,10^99,2995,1050) so that you see this on the main screen normalcdf(1900,10^99,2995,1050) Then press ENTER and you read .8514927476 ==================================== d. find the energy consumption level that separates the bottom 15% from the top 85% On your TI-83 or better calculator: Press 2nd VARS [to get DIST menu] Press 3 [to get invNorm( ] After " invNorm( " type this: .15,2995,1050) so that you see this on the main screen invNorm(.15,2995,1050) Then press ENTER and you read 1906.744951 ============================= Note: to use normalcdf( enter it this way: normalcdf(LOWER BOUND. UPPER BOUND, MEAN, STANDARD DEVIATION) If there is no lower bound, that is, if it is all the way to the left, use -10^99 as the lower bound. If there is no upper bound, that is, if it is all the way to the right, use 10^99 as the upper bound. Note: to use invNorm( enter it this way: invNorm(LOWER PERCENTAGE EXPRESSED AS A DECIMAL, MEAN, STANDARD DEVIATION) Edwin