SOLUTION: given the amount (oz) of juice in 10 randomly selected juice bottles are:
15.1, 15.6, 15.6, 15.9, 15.2, 15.9, 15.2,15.1, 15.8, 15.2.
construct a 94% confidence interval for the
Algebra.Com
Question 441910: given the amount (oz) of juice in 10 randomly selected juice bottles are:
15.1, 15.6, 15.6, 15.9, 15.2, 15.9, 15.2,15.1, 15.8, 15.2.
construct a 94% confidence interval for the mean amount of the juice, u(with a wierd line), in the population of all such bottles. assume that the population has a normal distribution.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In a sample of 60 mice, a biologist found that 46% were able to run a maze in 30 seconds or less. Find the 90% limit for the population proportion of mice who can run that maze in 30 seconds or less?
---------------------------
p-hat = 0.46
ME = 1.645*sqrt[0.46*0.54/60] = 0.1058
-----------
90% CI: 0.46-0.1058 < p < 0.46+0.1058
=========================================
Cheers,
Stan H.
RELATED QUESTIONS
The amounts (in ounces) of juice in eight randomly selected juice bottles are: 15.2 15.5... (answered by Boreal)
(-15)+(-8) -... (answered by josmiceli)
-|+15| (answered by Earlsdon)
15^3 *... (answered by mananth)
Find an equation for the nth term of the arithmetic sequence.
-15, -6, 3, 12, ...... (answered by ikleyn)
15 - 3 × 6 ÷ 1 +... (answered by lenny460)
2 (answered by tommyt3rd)
2 radical 15 - 6 radical 15 - 3 radical... (answered by jim_thompson5910)
6/15^2 (answered by killer6678)
15 ÷ 6 2/3... (answered by Cromlix)