Hi

 Mary has 30 hats. She has 5 green, 7 blue, 12 red, and 6 brown. 

 selects two hats at random

P(they are different colors) = 1 - P(both are the same color)

P(both are the same color) = 5/30*4/29 + 7/30*6/29 + 12/30*11/29 + 6/30*5*29

                           = (20 + 42 + 132 + 30)/30*29 =  224/30*29 = .2575

P(they are different colors) = 1 -.2575 = .7425  

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
 Mary has 30 hats. She has 5 green, 7 blue, 12 red, and 6 brown. If she selects two hats at random, what is the probability that both hats are different colors? Round your answer to two decimal places. 

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Ans: 1 - P(hats are same color)

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= 1 - [5C2 + 7C2 + 12C2 + 6C2]/30C2

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= 1 - [112/435]

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= 323/435

----

=0.743

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Cheers,

Stan H.

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