SOLUTION: find n for a 96% confidence interval for p with e=0.024 using an estimate of p=0.8 ( round to the nearest whole number)
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Question 436768: find n for a 96% confidence interval for p with e=0.024 using an estimate of p=0.8 ( round to the nearest whole number)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find n for a 96% confidence interval for p with e=0.024 using an estimate of p=0.8 ( round to the nearest whole number)
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Since e = z*sqrt(pq/n)
sqrt(n) = [z/e]*sqrt(pq)
n = [z/e]^2*pq
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n = [1.96/0.024]^2*0.8*0.2
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n = [81.67]^2*0.16
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n = 1067 when rounded
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Cheers,
Stan H.
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