Hi

Note: The probability of x successes in n trials is: 

P = nCx*  where p and q are the probabilities of success and failure respectively. 

In this case p = .6 and q = .4

nCx = 

X denotes the number of the ten vehicles randomly choses that were exceeding the limit 

a. P (X =10)  = (.6)^10

b. P (4 < x <9) = 252(.6)^5(.4)^5 + 210(.6)^6(.4)^4 +120(.6)^7(.4)^3 + 45(.6)^8(.4)^2



c. P (X = 2) = 45(.6)^2(.4)^8

d. P (3 ≤ X ≤ 6) = 

 120(.6)^3(.4)^7 + 210(.6)^4(.4)^6 + 252(.6)^5(.4)^5 + 210(.6)^6(.4)^4

 



 

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