Hi

Survey Results reveal that 45% of patients screened for a virus test positive

 p = .45  q = .55 

random sample of 35 patients

mean = .45*35 = 16 expected average number to test positive..

SD = sqrt(35*.55*.45) = ~3

P(9 test positive)is less than 2 SD left of mean ..very small probability < .02





 

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