Hi

Survey Results reveal that 45% of patients screened for a virus test positive

 p = .45  q = .55 

random sample of 35 patients

mean = .45*35 = 16 expected average number to test positive..

SD = sqrt(38*.55*.45) = ~3

P(between 13  and 19) = P (-1 > z <1) 1 SD from mean accounts  for 68.2% 



 

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