Hi

Survey Results reveal that 45% of patients screened for a virus test positive

 p = .45  q = .55 

random sample of 35 patients

mean = .55*35 = 16 expected average number to test positive..

SD = sqrt(35*.55*.45) = ~3

P(at most 18 test positive) that is nearly everything left of z=1, or (P = 84%)

Estimate would be somewhat less than that.



 

RELATED QUESTIONS

Survey Results reveal that 45% of patients screened for a virus test positive. from a... (answered by ewatrrr)

Survey Results reveal that 45% of patients screened for a virus test positive. from a... (answered by stanbon)

Survey Results reveal that 45% of patients screened for a virus test positive. from a... (answered by ewatrrr)

  
 
Hi
 from a random sample of  (answered by ewatrrr)

A survey claims that 9 out of 10 doctors recommend aspirin for their patients with... (answered by wgunther)

A survey claims that 9 out of 10 doctors (i.e., 90%) recommend brand Z for their patients  (answered by Boreal)

A medical research team selects three patients at random from a group of nine patients... (answered by jorel1380)

Suppose that 4% of all the patients are infected with the virus (event V),
P(V) =... (answered by ikleyn,math_tutor2020)

``During a drug trial for a new anitbotic, 45% of the people woh were given the drug... (answered by reviewermath)