Question 428384: The KY Department of Natural Resources personnel periodically inspects plots in eastern ky for evidence of elk habitation. suppose that 25% of the plots have evidence of elk habitation. if a sample of 10 were inspected, how would I find the probability that none have evidence of elk habitation?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The KY Department of Natural Resources personnel periodically inspects plots in eastern ky for evidence of elk habitation. suppose that 25% of the plots have evidence of elk habitation. if a sample of 10 were inspected, how would I find the probability that none have evidence of elk habitation?
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The KY Department of Natural Resources personnel periodically inspects plots in eastern ky for evidence of elk habitation. suppose that 25% of the plots have evidence of elk habitation. if a sample of 10 were inspected, how would I find the probability that none have evidence of elk habitation?
P(has elk) = 0.25
P(has no elk) = 0.75
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P(10 plots have no elk) = 0.75*10 = 0.0563
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Cheers,
Stan H.
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