SOLUTION: solve this : 2sin3x=1 when 0 < or equal to x < or equal to 90

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Question 425456: solve this :
2sin3x=1
when 0 < or equal to x < or equal to 90
Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
Solution: 2sin3x=1 => sin3x=1/2 => 3x=30(degree) =>x=10(degree)
Since the sinx is periodic function with period 2%28pi%29 we have:
x=2%28pi%29n%2B10 for 0< x <90
The solution in radian will be:
sin%283x%29=1%2F2

+3x=%28pi%29%2F6
+x=%28pi%29%2F18 and the solution will be:
x=2%2A%28pi%29%2An%2B%28pi%29%2F18
+0+%3C+x+%3C+%28pi%29%2F2