SOLUTION: a ceramic jar contains 48 quarters and 21 dimes. If two coins are randomly drawn in sucession, without replacement, what is the probaility that the total value of the coins is $.20

Question 423803: a ceramic jar contains 48 quarters and 21 dimes. If two coins are randomly drawn in sucession, without replacement, what is the probaility that the total value of the coins is $.20

Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
We have 48Q and 21D. The total number of coins in the jar = 69.
The total value of the coins = $0.20 means we need the probability of selecting two dimes. For the first draw the probability of selecting a dime = 21/69 since there are 21 dimes and 69 total coins. For the 2nd draw, since the first dime wasn't replaced, there are 20 dimes remaining and 68 total coins. Therefore, the probability of selecting a dime = 20/68.
The probability of selecting two dimes is the product of these: P(2 dimes) = (21/69)*(20/68) = 0.0895
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