# SOLUTION: Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640. The chart below summarizes the 2008 population for five U.S. States. State 2008 Pop

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640. The chart below summarizes the 2008 population for five U.S. States. State 2008 Pop      Log On

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 Algebra: Probability and statistics Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Probability-and-statistics Question 422940: Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640. The chart below summarizes the 2008 population for five U.S. States. State 2008 Population Missouri 5,911,605 Pennsylvania 12,448,279 Tennessee 6,214,888 Utah 2,736,424 Washington 6,549,224 SOURCE: U. S. Census Bureau What is the probability that a randomly selected U.S. resident did not live in Utah? Show step by step work. Round solution to the nearest thousandth. Answer by htmentor(789)   (Show Source): You can put this solution on YOUR website!It seems that the only relevant information in this problem is the population of Utah, and the total U.S. population. The probability, P, that the person lives in Utah = Population of Utah divided by the U.S. population: P = 2,736,424/303,824,640 = 0.009 The probability that the person DID NOT live in Utah = 1 - P = 1 - 0.009 = 0.991