Question 422940: Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640. The chart below summarizes the 2008 population for five U.S. States.
State 2008 Population
SOURCE: U. S. Census Bureau
What is the probability that a randomly selected U.S. resident did not live in Utah? Show step by step work. Round solution to the nearest thousandth.
Answer by htmentor(789) (Show Source):
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It seems that the only relevant information in this problem is the population of Utah, and the total U.S. population.
The probability, P, that the person lives in Utah = Population of Utah divided by the U.S. population:
P = 2,736,424/303,824,640 = 0.009
The probability that the person DID NOT live in Utah = 1 - P = 1 - 0.009 = 0.991