# SOLUTION: the digits 1, 2, 3, 4, 5, and 7 are randomly arranged to form a six-digit number. Find the probability that the first and last digits are both even.

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: the digits 1, 2, 3, 4, 5, and 7 are randomly arranged to form a six-digit number. Find the probability that the first and last digits are both even.      Log On

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 Question 422870: the digits 1, 2, 3, 4, 5, and 7 are randomly arranged to form a six-digit number. Find the probability that the first and last digits are both even.Answer by sudhanshu_kmr(1152)   (Show Source): You can put this solution on YOUR website! no. of ways to arrange these 6 digits = 6! no. of ways to arrange 6 digits where first and last digit are even = no. of ways to arrange first and last digit * no. of ways to arrange 4 inner digits = 2! * 4! = 2 * 24 = 48 required probability = 48/6! = 48/720 = 1/15