Let P(8 or more) = x
x P(x)
0 0.327
1 0.206
2 0.07
3 0.097
4 0.028
5 0.022
6 0.01
7 0.24
8 or more x
--------------
1.000
The sum of all probabilities must have sum 1
0.327+0.206+0.07+0.097+0.028+0.022+0.01+0.24+x = 1
1+x = 1
x = 0
So the probability of buying 8 or more is 0.
Edwin