SOLUTION: In a Sample of 500 people, 60 are left handed. Two random people are chosen from the sample. Find the probability that both are left handed, that both are not left handed and that

Question 421315: In a Sample of 500 people, 60 are left handed. Two random people are chosen from the sample. Find the probability that both are left handed, that both are not left handed and that at least one of the two people are left handed.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In a Sample of 500 people, 60 are left handed. Two random people are chosen from the sample.
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Find the probability that both are left handed: (60C2)/500C2 = 1770/124750
= 0.0142
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that both are not left handed: 440C2/500C2 = 0.7742
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that at least one of the two people are left handed.
P(at least one) = 1 - P(none left handed) = 1-0.7742 = 0.2258
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Cheers,
Stan H.
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