SOLUTION: How do you solve inclusive events and mutually exclusive events dealing with probability?

Question 415541: How do you solve inclusive events and mutually exclusive events dealing with probability?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do you solve inclusive events and mutually exclusive events dealing with probability?
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Exclusive events are events that cannot happen simultaneously.
You cannot have hht and hth when you throw a coin 3 times.
So the probability of hht or hth = (1/8)+(1/8) = 1/4
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Inclusive events are events that can happen simultaneouly.
You can simultaneously draw a face card and a club from
a deck of cards.
So P(face or club) = 12/52 + 13/52 - 4/52 = 21/52
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Cheers,
Stan H.
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