SOLUTION: in a bag of 4 yellow and 8 blue marbles. three are selected at random without replacement. what is the probabilitlity that all 3 are yellow or all 3 are blue?
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Question 414461: in a bag of 4 yellow and 8 blue marbles. three are selected at random without replacement. what is the probabilitlity that all 3 are yellow or all 3 are blue? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! in a bag of 4 yellow and 8 blue marbles. three are selected at random without replacement. what is the probabilitlity that all 3 are yellow or all 3 are blue?
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P(3 blue) = 8C3/12C3
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P(3 yellow) = 4C3/12C3
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P(3 blue or 3 blue) = [8C3 + 4C3]/12C3 = [56 + 4]/[12*11*10/6]
= [6*60/[1320] = 0.273
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Cheers,
Stan H.
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