Hi

there are 200 pieces of bubble gum in a bubble gum machine of which:

* Forty pieces are blue.

* Thirty-five pieces are red* P(RED)= .175

* Thirty pieces are green.

* Fifty pieces are yellow.

* Forty-five pieces are white. 

If four pieces of bubble gum are purchased... 

Note: The probability of x successes in n trials is: 

P = nCx*  where p and q are the probabilities of success and failure respectively. 

In this case p = .175 AND q = .825

nCx = 



what is the probability of getting at least two pieces of red gum?

 P(at least two pieces of red gum) = 1 - P(1) - P(0)

 P = 1- 4(.175)*(.825)^3 - .825^4 = .1437 

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