SOLUTION: The mean of a normal probability distribution is 87 and the standard deviation is 4. What is the probability of a value greater than 90? A) .2734 B) .7734 C) .2420 D) .2264

Question 408193: The mean of a normal probability distribution is 87 and the standard deviation is 4. What is the probability of a value greater than 90?
A) .2734
B) .7734
C) .2420
D) .2264

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi

mean of a normal probability distribution is 87 and the standard deviation is 4. 

*Note: 

  z = (90-87)/4 = 3/4 = .75  |NORMSDIST(0.75) = .77337

 P(z > .75) = 1 - .77337 = .25335 

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