SOLUTION: Given a set of data with a mean of 150 and a standard deviation of 25. Using Chebyshev's Theorem, what is the minimum percentage of data between 75 and 225?

Algebra ->  Probability-and-statistics -> SOLUTION: Given a set of data with a mean of 150 and a standard deviation of 25. Using Chebyshev's Theorem, what is the minimum percentage of data between 75 and 225?      Log On


   

Question 404116: Given a set of data with a mean of 150 and a standard deviation of 25. Using Chebyshev's Theorem, what is the minimum percentage of data between 75 and 225?
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
75 = 150 - 3*25 = 75, and 225 = 150 + 3*25 .
Hence k = 3 in Chebyshev's theorem (or, within 3 sd's from the mean, plus-minus).
==> P%28abs+%28X+-+mu%29+%3C=+3sigma%29+%3E=+1+-+1%2F3%5E2+=+8%2F9.
That is AT LEAST 88%268%2F9% of the distribution between 75 and 225.