SOLUTION: A box contains 28 transitors, 5 of which are defective. If 5 are sold at random, find the probability that at least 1 is defective. Express your answer as a fraction.
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Question 403626: A box contains 28 transitors, 5 of which are defective. If 5 are sold at random, find the probability that at least 1 is defective. Express your answer as a fraction. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A box contains 28 transitors, 5 of which are defective. If 5 are sold at random, find the probability that at least 1 is defective. Express your answer as a fraction.
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P(>=1 defective) = 1 - P(none defective)
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= 1 - 28C5/33C5
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= 1 - 0.4141
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= 0.5859
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Cheers,
Stan H.
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