SOLUTION: Two different awards are to be given to two different dogs at the dog show. If there are 12 Labradors, 18 Collies and 5 Shelties, how many different ways can the awards be presen

Question 40344: Two different awards are to be given to two different dogs at the dog show. If there are 12 Labradors, 18 Collies and 5 Shelties, how many different ways can the awards be presented?
Two different awards are to be given to students who attend Cal Poly. The nominees included 9 Accounting majors, 6 Math majors, and 2 Biology majors. In how many different ways can the awards be given to students with different majors?
Twenty of the houses on a street receive cable t.v. and seven do not. A researcher studying the amount of time that people watch t.v. intends to visit five of the houses that receive cable t.v and two that do not. How many such selections of houses are there?

If the probability that A occurs is .21, the probability that B occurs is .34, and the probability that both occur is .05. What is the probability that A does not occur? Round your answer to two decimal places.

Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
Two different awards are to be given to two different dogs at the dog show. If there are 12 Labradors, 18 Collies and 5 Shelties, how many different ways can the awards be presented?
P(35,2) = 1190
Two different awards are to be given to students who attend Cal Poly. The nominees included 9 Accounting majors, 6 Math majors, and 2 Biology majors. In how many different ways can the awards be given to students with different majors?
(9*6)+(9*2)+(6*9)+(6*2)+(2*9)+(2*6)
54+18+54+12+18+12 = 168
Twenty of the houses on a street receive cable t.v. and seven do not. A researcher studying the amount of time that people watch t.v. intends to visit five of the houses that receive cable t.v and two that do not. How many such selections of houses are there?
C(20,5)C(7,2) = 15504*21 = 325,584
If the probability that A occurs is .21, the probability that B occurs is .34, and the probability that both occur is .05. What is the probability that A does not occur? Round your answer to two decimal places.
1.00 - P(A) = P(-A)
1.00 - 0.21 = 0.79 or 79%

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