You can
put this solution on YOUR website!P(scores) = 0.6, so that P(misses) = 0.4
P(score) and P(score again) = 0.6*0.6 = 0.36
P(score) and P(miss) = 0.6*0.4 = 0.24
P(miss) and P(score) = 0.4*0.6 = 0.24
P(miss) and P(miss again) = 0.4*0.4 = 0.16
so we can now think about the possible situations:
P(no score) = 0.16
P(score=1) = 0.24+0.24 = 0.48
P(score=2) = 0.36
So, most likely to score 1 point.
jon