SOLUTION: in a shipment of 30 televisions, 4 are defective. if 3 television sets are randomly selected and tested without replacement, what is the probability that the three are defective?

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Question 393166: in a shipment of 30 televisions, 4 are defective. if 3 television sets are randomly selected and tested without replacement, what is the probability that the three are defective?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
Note: The probability of x successes in n trials is:
P = nCx* where p and q are the probabilities of success and failure respectively.
In this case let p(defective) = 4/30 = 2/15 & q = 7/15
nCx =
P(3 chosen are all defective) = (2/15)^3 = .0024
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