SOLUTION: A poll found that 45% of the workers at the company take the bus instead of the car to work to save money. if 4 workers are selected at random what is the probability that at least

Question 393165: A poll found that 45% of the workers at the company take the bus instead of the car to work to save money. if 4 workers are selected at random what is the probability that at least 1 worker take the bus instead of the car to work?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi

Note: The probability of x successes in n trials is: 

P = nCx*  where p and q are the probabilities of success and failure respectively. 

In this case p(taking the bus)= .45 & q = .55

nCx = 

P(out of 4, at least one takes bus) = 1-P(none taking bus) = 1 - (.55)^4

P(out of 4, at least one takes bus) = 1 - (.55)^4 = 1 - .0915 = .9085 

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