SOLUTION: A shipment contains 8 TV's, of which two are defective. A sample of three TV's is selected at random. In how many ways can no defective TV's be chosen?
A firm has 19 senior and
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Question 392332: A shipment contains 8 TV's, of which two are defective. A sample of three TV's is selected at random. In how many ways can no defective TV's be chosen?
A firm has 19 senior and 28 junior partners. A committee of three partners is selected at random to represent the firm at a conference. In how many ways can at least one of the junior partners be chosen to be on the committee?
Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!
2 TVs are defective, 6 non-defective
no. of ways to choose 3 TVs randomly from 8 = 8C3 = 56
no. of ways to choose 3 non-defective TVs = 6C3 = 20
probability of no defective TVs in randomly selected 3 TVs = 20/56
....please write the question same as it is given on book or assignment.
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