SOLUTION: Suppose the Q-angles (measured standing) for a population of young adult women are normally distributed with a mean of 19 degrees and standard deviation of 8 degrees. Let us call t

Question 392118: Suppose the Q-angles (measured standing) for a population of young adult women are normally distributed with a mean of 19 degrees and standard deviation of 8 degrees. Let us call this variable X.
What is the probability that a randomly chosen X-value is less than 24 degrees?
What is the probability that a randomly chosen X-value is greater than 24 degrees?

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi

*Note: 

  z = (24-19)/8 = 5/8 = .626     |using the  Excel NORMSDIST(0.626) function

  P(z < 24) = .7343      P(z > 24) = 1 -.7343 = .2657 

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