SOLUTION: an unfair coin will turn up heads 4 out of 5 times (i.e. P(heads)=0.8). what is the probability that
a) on three tosses we get a heads, then a tails, then a heads.
b) on two toss
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Question 391927: an unfair coin will turn up heads 4 out of 5 times (i.e. P(heads)=0.8). what is the probability that
a) on three tosses we get a heads, then a tails, then a heads.
b) on two tosses we get a heads and a tails (in any order)
Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!
probability of getting heads = 0.8 and for getting tails = 0.2
a) probability of getting a heads, then a tails then a heads = 0.8 * 0.2 * 0.8
= 0.128
b) probability of different cases
case 1: firstly head then tail = 0.8 * 0.2 = 0.16
case 2 : firstly tail then head = 0.2 *0.8 = 0.16
thus, total probability of a heads and a tail = 0.16 + 0.16 = 0.32
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