SOLUTION: we have 2 boys and 4 girls to be seated in a 6-seat row at the movie theatre. What is the probability that the two people at the end of the row were both boys or both girls? Expres
Algebra.Com
Question 388906: we have 2 boys and 4 girls to be seated in a 6-seat row at the movie theatre. What is the probability that the two people at the end of the row were both boys or both girls? Express your answer as a common fraction?
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
nPr=permutations of n things taken r at a time=n!/(n-r)!
Both boys=4!*2=48 ways
Both girls=4P2*4!=12*24=288 ways
(48+288)/6!=336/720=7/15
.
Ed
RELATED QUESTIONS
We have 2 girls and 4 boys to be seated ina 6-seat row at the movie theater. What is the... (answered by edjones)
In how many ways can a teacher seat 4 girls and 2 boys in a row of 6 seats if the 2 boys... (answered by ewatrrr)
In how many ways can 4 boys and 4 girls be seated in a row if a. they can seat anywhere... (answered by mccravyedwin)
5 boys and 3 girls are to be seated on chairs arranged in a row. If the arrangement is... (answered by Edwin McCravy)
In how many ways can 4 boys and 2 girls seat themselves in a row if the two girls are NOT (answered by sudhanshu_kmr)
2 girls and 4 boys are to be seated in a row of 5 chairs. Find the number of ways they... (answered by ikleyn)
in how many ways can 4 boys and 2 girls be seated if
i)the 2 girls are to seat next to... (answered by Edwin McCravy)
1. From a box containing 6 red bulbs, 8 yellow bulbs and blue bulbs, two bulbs is drawn. (answered by consc198,venugopalramana)
hi good morning!
I would like to know how to answer these following problems. thank... (answered by psbhowmick)