SOLUTION: show all work..................... a disc jockey has 7 songs to play. five are slow songs, and two are fast songs. each song is to be played only once. in how many ways can the

Algebra.Com
Question 384654: show all work.....................
a disc jockey has 7 songs to play. five are slow songs, and two are fast songs. each song is to be played only once. in how many ways can the disc jockey play 7 songs if
the song can be played in any oder
the first song must be a slow song and the last song must be a slow song
the first two songs must be fast songs

Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
2 fast and 5 slow songs.
a)7!=5040 ways
.
b)
5P2=20 Permutations of the 1st and last
5!=120 permutation of the middle 5.
20*5!=2400 ways
.
c) 2*5!=240 ways.
.
Ed

RELATED QUESTIONS

5. Show all work. A disc jockey has 12 songs to play. Seven are slow songs, and five are... (answered by allig,lstoney)
Show all work. A disc jockey has 7 songs to play. 5 are slow songs, and 2 are fast songs. (answered by stanbon)
Show all work. A disc jockey has 7 songs to play. Three are slow songs, and four are fast (answered by stanbon)
5. Show all work. A disc jockey has 10 songs to play. Seven are slow songs, and three are (answered by Alan3354)
Show all work. A disc jockey has 11 songs to play. Eight are slow songs, and three are... (answered by stanbon)
can you please help me? show all work, a disk jockey has 9 songs to play. 5 are slow,... (answered by stanbon)
I find this question to be very confusing. Can someone please help with it? Thank you (answered by solver91311)
A disc jockey has 10 songs to play. Four are slow songs, and six are fast songs. Each... (answered by sudhanshu_kmr)
A disc jockey has 11 songs to play. Eight are slow songs, and three are fast songs.... (answered by stanbon)