# SOLUTION: a die is tossed 4 times. what is the odds in favor of the die showing a 6 all four times.

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 Click here to see ALL problems on Probability-and-statistics Question 382862: a die is tossed 4 times. what is the odds in favor of the die showing a 6 all four times. Answer by stanbon(57967)   (Show Source): You can put this solution on YOUR website!a die is tossed 4 times. what is the odds in favor of the die showing a 6 all four times. ------ P(6 four times) = (1/6)^4 P(not getting 6 four times) = 1 - (1/6)^4 ---------------------------------------------- Odds in favor of "6 four times" = [1/6^4]/[1 - (1/6^4)] = [1/6^4]/[(6^4-1)/6^4] -------------- = 1:1295 ================ Cheers, Stan H.