SOLUTION: a bag contains 4 red tiles, 3 blue tiles, 2 green tiles, and 1 yellow tile. A tile is drawn from the bag and not returned. Then a second tile is drawn. What is the probability that

Question 382402: a bag contains 4 red tiles, 3 blue tiles, 2 green tiles, and 1 yellow tile. A tile is drawn from the bag and not returned. Then a second tile is drawn. What is the probability that the first tile is blue and the second tile is blue?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Note: there are 4+3+2+1 = 10 tiles total. Also, because we're NOT replacing tiles we've selected, this means that as we draw more tiles out, the total will go down (along with the count of the color tile we just drew)

So if we start with 3 blue tiles (out of 10 total) and draw one, we'll have 2 blue left over (out of 9 total), which means that

P(Blue AND Blue) = P(Blue)*P(Blue) = (3/10)*(2/9) = (3*2)/(10*9) = 6/90 = 1/15

So the probability that the first tile is blue and the second tile is blue is (with no replacement).
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