SOLUTION: Suppose one card is selected at random from an ordinary deck of 52 playing cards. let A= event a diamond is selected B= event a club is selected Determine P(A/(not B))

SOLUTION: Suppose one card is selected at random from an ordinary deck of 52 playing cards. let A= event a diamond is selected B= event a club is selected Determine P(A/(not B))

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Question 381223: Suppose one card is selected at random from an ordinary deck of 52 playing cards. let
A= event a diamond is selected
B= event a club is selected
Determine P(A/(not B))
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Since we're given that event B did NOT happen, this means that there are 52-13 = 39 remaining cards to choose from.

Since there are 13 diamond cards, this means that the probability is
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