SOLUTION: if there are 2 red, 4 green and 6 blue m&m's left in a packet, what is the probability of next picking a green one?
Algebra.Com
Question 379842: if there are 2 red, 4 green and 6 blue m&m's left in a packet, what is the probability of next picking a green one?
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
The probability is
#(greens)/#(total)
= 4/12 = 1/3.
RELATED QUESTIONS
A bag of M&M's has 2 red, 7 green, 5 blue, and 4 yellow M&M's. What is the probability of (answered by ewatrrr)
A bag of M&M's has 5 red, 3 green, 8 blue, and 6 yellow M&M's. What is the probability of (answered by ikleyn)
A bag of M & M's has 6 red, 4 green, 8 blue and 7 yellow . What is the probability of... (answered by math_tutor2020)
A bag of M&M's has 6 red, 5 green, 7 blue, and 3 yellow M&M's. What is the probability of (answered by Fombitz)
What is the probability of picking a green marble? If there is 10 green marbles and 4 red (answered by nyc_function)
A bag of M&M's has 6 red, 3 green, 8 blue, and 4 yellow M&M's. What is the probability of (answered by rfer)
(There is 3 Blue, 8 Red, 12 Green, 12 Yellow, 4 Brown, and 2 Orange.)
When you open a... (answered by ewatrrr)
A jar contains 12 M&M candies, of the 12: 2 are red, 3 are green, 3 are blue, 4 are... (answered by ewatrrr)
In a bag of M&M’s there are 12 green, 7 blue, 11 brown, 9 orange, and 15 red candies.... (answered by MathGeek87,swincher4391)