Hi,

12 different choices of which 6 are different concerts P(a concert) = 6/12 = 1/2

P(attending three concerts) = 6/12 * 5/11 * 4/10 



12 different choices of which 4 are different plays and 2 are different BB games

P(Two plays and one basketball game) = 4/12 * 3/11 * 2/10



P(One movie, one play, and one basketball game) = 0   (movie not a option) 

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