Hi,
Note: The probability of x successes in n trials is:
P = nCx*where p and q are the probabilities of success and failure respectively.
In this case p = .10 and q = .90
P(exactly 2 out of 14 will have side effects):
P = 14C2 (.10)^2(.90)^12 = 81 *(.10)^2(.9)^12 = .257
P(at least three will have side effects):
P = 1 - P(none) - P(one) - P(two) = 1- (.9)^14 - 17*(.1)^1(.9)^13 - 136*(.1)^2(.9)^12
P = 1 -.2288 - .3559 - .2570 = .1584