SOLUTION: The mean concentration of carbon dioxide is 365 parts per million with a standard deviation of 100 parts per million. Take a sample from 25 cities. Describe the sampling distribu

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Question 377628: The mean concentration of carbon dioxide is 365 parts per million with a standard deviation of 100 parts per million. Take a sample from 25 cities. Describe the sampling distribution of the sample mean. Find the probability that the sample mean concentration will be above 385 parts per million.
So far, I am able to figure
(385-365)/(100/(sqrt 25)) = 0.0527
At this point, checking the Z table I get the value of 0.06031. I'm not sure where I go from here in finishing this problem. Any help would be greatly appreciated.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi

(385-365)/(100/(sqrt 25)) = 20/20 = 1 Note: 

Z table or NORMSDIST(1)= .8413

1 - .8413 = .1587 Or 15.87% is the probability that the sample mean concentration will be above 385 parts per million. 

 

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