Hi,

*Note: Formula for the test statistic is 

In this case n = 10

Entering the Data into an Excel worksheet column and applying the Data Analysis tool

found  and  for this sampling.

 = -3.8/2.328 = -1.632

P(t < -1.632) can be found using the NORMSDIST(-1.632)function in Excel

or by looking at an usual standard normal table.

P(t < -1.632) = .05134 or 5.1%

The test results show that this sampling is in the low range of normal hearing 

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