SOLUTION: X is a normal variate with mean 30 and standard deviation 5. Find the probabilities that 1. 26< X <40 2. x>45

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Question 373584: X is a normal variate with mean 30 and standard deviation
5. Find the probabilities that
1. 26< X <40
2. x>45

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
*Note:
P(26< X <40)
z = 40-30/5 = 2
z = 26-30/5 = -.8
using the excel normdist functon
NORMSDIST(2) = .97725
NORMSDIST(-0.8)= .21186
P(26< X <40) = .97725 - .21186 = .76539
P(x>45)
z = 45-40/5 = 1
NORMSDIST(1)= .841345
P(x>45) = 1 - .841345 = .15866
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